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3x^2+46x-32=0
a = 3; b = 46; c = -32;
Δ = b2-4ac
Δ = 462-4·3·(-32)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(46)-50}{2*3}=\frac{-96}{6} =-16 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(46)+50}{2*3}=\frac{4}{6} =2/3 $
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